# Line slope calculator 4x-3y=-3

**Straight line given by points A[0; 1] and B[3; 5]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x+1

**Canonical form of the line equation:**4x-3y+3 = 0

**Parametric form of the line equation:**

x = 3t

y = 4t+1 ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= -0.75

**Y intercept:**y

_{0}= q = 1

**Distance line from the origin:**d

_{0}= 0.6

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[1.5; 3]

**Perpendicular Bisector equation:**3x+4y-16.5 = 0

**Vector OA = (0; 1) ; |OA| = 1**

**Vector OB = (3; 5) ; |OB| = 5.831**

**Scalar product OA .OB = 5**

**Angle ∠ AOB = 30°57'50″ = 0.5404 rad**