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C.2 The Finite Potential Well

   To show that the infinite well approximation is sufficient in our case, the energy levels of a finite potential well, Fig. C.2, are calculated and compared to (C.10).
  
Figure C.2: Finite potential well with width d and height E0. On the right side a comparison of the first ten energy levels for an infinite potential well of width 10 nm and a finite well with the same width and a height of 0.34 eV is shown. The first levels differ only slightly.
$\textstyle \parbox{20cm}{
\includegraphics{finit_well.eps}
\resizebox{8cm}{!}{\includegraphics{el_finit_well.eps}}}$

The Ansatz for the three regions is
\begin{alignat}{2}
&\psi_1=A_1e^{k_1x} &\qquad &k_1=\frac{1}{\hbar}\sqrt{2m^*(E_...
...uad
&k_2=\frac{1}{\hbar}\sqrt{2m^*E}\\
&\psi_3=B_3e^{-k_1x} & &
\end{alignat}
The boundary conditions yield the following equations:
\begin{alignat}{2}
&A_1=A_2+B_2 &\qquad &A_2e^{\text{i}k_2d}+B_2e^{-\text{i}k_2d...
...^{\text{i}k_2d}-\text{i}k_2B_2
e^{-\text{i}k_2d}=-k_1B_3e^{-k_1d}
\end{alignat}
Solving for A2 gives
\begin{gather}A_2\left[\left(1+\frac{\text{i}k_2}{k_1}\right)^2e^{\text{i}k_2d}-
\left(1-\frac{\text{i}k_2}{k_1}\right)^2e^{-\text{i}k_2d}\right]=0
\end{gather}
Since the trivial solution A2=0 is not of interest, the second term has to be zero. This is the condition fulfilled only for special energies. The transcendent condition can be written as
\begin{gather}\frac{2\sqrt{E(E_0-E)}}{2E-E_0}=\tan\left(\frac{d\sqrt{2m^*E}}{\hbar}\right),
\end{gather}
which is only numerically solvable. A quantitative comparison is given for $d\sqrt{2m^*E_0}/\hbar=30$, which corresponds to a well with a width of 10 nm and a height of 0.34 eV, in the right side of Fig. C.2. The first energy levels differ only slightly.


next up previous index
Next: C.3 The Rectangular Potential Up: C Solutions to Schrödinger's Previous: C.1 The Infinite Potential

Christoph Wasshuber